回答:以oracle為例:SELECT * FROM(SELECT A.*, ROWNUM RNFROM (SELECT rs.student_id,count(1) FROM relationship rs group by rs.student_id order by count(1) desc) AWHERE ROWNUM = 0
...和課程類 課程類 /imooc_collection_map_demo/src/com/imooc/collection/Course.java package com.imooc.collection; //課程類 public class Course { public String id; public String name; public Cour...
...AULT CHARSET=utf8; DESC `teacher`; # 創建課程表 DROP TABLE IF EXISTS `course`; CREATE TABLE `course`( `cid` INT UNSIGNED NOT NULL AUTO_INCREMENT , `cname` VARCHAR(50) NOT NULL , `teacher_id`...
運行結果: 數據庫的2個表:course表 student表 ps:一定要build path導入數據庫用的jar包,以及在在lib文件夾中導入數據庫jar包 文件目錄結構: 具體代碼:index.jsp 首頁 歡迎進入選課系統 歡迎進入選課 系統 學生登錄 ...
運行結果: 數據庫的2個表:course表 student表 ps:一定要build path導入數據庫用的jar包,以及在在lib文件夾中導入數據庫jar包 文件目錄結構: 具體代碼:index.jsp 首頁 歡迎進入選課系統 歡迎進入選課 系統 學生登錄 ...
...* ArrayList的增刪改查 * */ public class ListTest { private List coursesList; // 備選課程列表 public ListTest() { this.coursesList = new ArrayList(); } public List getCour...
Course Schedule I There are a total of n courses you have to take, labeled from 0 to n - 1.Some courses may have prerequisites, for example to take course 0 you have to first take course 1, which is e...
...具體的實現 /** * 課程教練類 */ public class Coach { private CourseBuilder courseBuilder; public void setCourseBuilder(CourseBuilder courseBuilder) { this.courseBuilder = courseBuilder; ...
... return .format(self.name) 一對多關系現在創建第二個映射類 Course,它對應的數據表 course 存放課程數據。一個課程作者可以創建多個課程,一個課程對應唯一的課程作者,這種關系被稱為一對多或者多對一關系,這是最常用的數據...
Course Schedule Problem There are a total of n courses you have to take, labeled from 0 to n - 1. Some courses may have prerequisites, for example to take course 0 you have to first take course 1, whi...
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大模型的訓練用4090是不合適的,但推理(inference/serving)用4090不能說合適,...
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