...aracter 統計data[i]后8位里面,從前開始有多少個1,用變量ones來保存,其中ones可能的值只有0, 2, 3, 4 從 data[i+1] 開始檢查,后八位中的前兩位是否為10,一共檢查ones - 1 更新i的值為 i + ones public class Solution { public boolean validUtf8(...
...(HKEY_CURRENT_USERSoftwareMicrosoftWindowsCurrentVersionInternet Settingsones11001,0,REG_DWORD); WshShell.RegWrite(HKEY_CURRENT_USERSoftwareMicrosoftWindowsCurrentVersionInternet Setting...
... One-pass, constant extra space. Note 假設數a第一次出現,只存在ones里,第二次出現,從ones里消去,然后存在twos里,第三次出現,由于ones不存取已經在twos里的數,就只從twos里消去。整個過程相當于,直接在ones和twos里去掉既是ones又是...
Ones and Zeroes 題目鏈接:https://leetcode.com/problems... knapsack problem,這里是最基本的01背包,把cost變成了二維的。參考背包九講:http://love-oriented.com/pack... public class Solution { public int findMaxForm(String[] strs,...
...章地址 第一題 What is the result of this expression? (or multiple ones) [1, 2, 3].map(parseInt) A:[1, 2, 3] B:[1, 2, 3] C:[0, 1, 2] D:other 解答:這里考的是map、parseInt的用法。map會傳遞三個參數給其作為參數的函數,為(element...
D67 485. Max Consecutive Ones 題目鏈接 485. Max Consecutive Ones 題目分析 給定一個二進制數組(只含有0和1的數組),返回最長的1串。 思路 逐個遍歷,若為1則計數。遇到0則判斷當前計數是否大于之前記錄的最大數字,并置零。 返回...
Max Consecutive Ones 題目鏈接:https://leetcode.com/problems... public class Solution { public int findMaxConsecutiveOnes(int[] nums) { // loop invariant: // global is the max so far, ...
..._sym], results) # 測試 x = np.eye(2, dtype=theano.config.floatX) w = np.ones((2, 2), dtype=theano.config.floatX) b = np.ones((2), dtype=theano.config.floatX) b[1] = 2 compute_elementwise(x, w, b) #...
...import cv2 import numpy as np img = cv2.imread(img7.png,0) kernel = np.ones((5,5),np.uint8) erosion = cv2.erode(img,kernel,iterations = 1) cv2.imshow(src,img) cv2.imshow(show,erosion) cv2.waitKe...
... Java 注釋。 Java: class Solution{ public int findMaxConsecutiveOnes(int[] nums) { int temp=0,count=0;//temp記錄當前連續1的個數,count記錄當前最大連續1的個數 for (int i=0;i int: count=temp=0 ...
...1最后應該全是0。 public int singleNumber(int[] A) { int ones = 0, twos = 0; for(int i = 0; i < A.length; i++){ ones = (ones ^ A[i]) & ~twos; twos = (twos ^ A[i]...
... Java 注釋。 Java: class Solution{ public int findMaxConsecutiveOnes(int[] nums) { int temp=0,count=0;//temp記錄當前連續1的個數,count記錄當前最大連續1的個數 for (int i=0;i int: count=temp=0 ...
...it efficiently? Solution class Solution { public int findMaxConsecutiveOnes(int[] nums) { int max = 0, lastZeroIndex = -1; int l = 0, r = 0; while (r < nums.length) { ...
... Java 注釋。 Java: class Solution{ public int findMaxConsecutiveOnes(int[] nums) { int temp=0,count=0;//temp記錄當前連續1的個數,count記錄當前最大連續1的個數 for (int i=0;i int: count=temp=0 ...
...{ const bits = new Array(n + 1).fill(0); for (let i = 0; i { let ones = 0; while (x > 0) { x &= (x - 1); ones++; } return ones;}Java:class Solution { public int[...
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