Problem
Given a complete binary tree, count the number of nodes.
Note:
Definition of a complete binary tree from Wikipedia:
In a complete binary tree every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible. It can have between 1 and 2h nodes inclusive at the last level h.
Example:
Input: 1 / 2 3 / / 4 5 6 Output: 6Solution
class Solution { public int countNodes(TreeNode root) { if (root == null) return 0; int height = 0; TreeNode left = root.left, right = root.right; while (left != null && right != null) { height++; left = left.left; right = right.right; } if (left == null && right == null) return (1 << (height+1)) - 1; else return 1 + countNodes(root.left) + countNodes(root.right); } }
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