Problem
Let"s call an array A a mountain if the following properties hold:
A.length >= 3
There exists some 0 < i < A.length - 1 such that A[0] < A[1] < ... A[i-1] < A[i] > A[i+1] > ... > A[A.length - 1]
Given an array that is definitely a mountain, return any i such that A[0] < A[1] < ... A[i-1] < A[i] > A[i+1] > ... > A[A.length - 1].
Example 1:
Input: [0,1,0]
Output: 1
Example 2:
Input: [0,2,1,0]
Output: 1
Note:
3 <= A.length <= 10000
0 <= A[i] <= 10^6
A is a mountain, as defined above.
class Solution { public int peakIndexInMountainArray(int[] A) { int start = 0, end = A.length-1; while (start+2 < end) { int mid = start+(end-start)/2; if (mid-1 >= start && mid+1 <= end && A[mid-1] < A[mid] && A[mid] > A[mid+1]) { return mid; } else if (mid-1 >= start && mid+1 <= end && A[mid-1] < A[mid] && A[mid] < A[mid+1]) { start = mid; } else if (mid-1 >= start && mid+1 <= end && A[mid-1] > A[mid] && A[mid] > A[mid+1]) { end = mid; } else { break; } } return start+1; } }
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